A gamma ray photon creates an electron-positr | vedclass

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(B) The process of pair production involves a gamma ray photon creating an electron-positron pair.The total energy of the gamma ray photon $(E_{\gamma

Vedclass · Accepted Answer

$1.78$

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(B) The process of pair production involves a gamma ray photon creating an electron-positron pair.The total energy of the gamma ray photon $(E_{\gamma})$ must be equal to the sum of the rest mass energies of the electron and positron plus their total kinetic energy $(K.E.)$.The rest mass energy of an electron is $m_e c^2 = 0.5 \, MeV$.The rest mass energy of a positron is also $m_e c^2 = 0.5 \, MeV$.Given the total kinetic energy of the pair is $0.78 \, MeV$.Therefore,$E_{\gamma} = (m_e c^2)_{	ext{electron}} + (m_e c^2)_{	ext{positron}} + K.E._{	ext{total}}$.$E_{\gamma} = 0.5 \, MeV + 0.5 \, MeV + 0.78 \, MeV = 1.78 \, MeV$.

$A$ gamma ray photon creates an electron-positron pair. If the rest mass energy of an electron is $0.5 \, MeV$ and the total $K.E.$ of the electron-positron pair is $0.78 \, MeV$,then the energy of the gamma ray photon must be .......... $MeV$.

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